1982 AHSME Problems/Problem 4

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by mathhayden (bad)

perimeter=2r+pi2r=2r(pi+1)

area=[pi(r^2)]/2

make them equal & solve for r: pi(r^2)/2=2r(pi+1) pi(r^2)=4r(pi+1) (r^2)=4r[(pi+1)/pi] r=4(pi+1)/pi

=$4\pi+4/pi$   Ans.
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