1983 AHSME Problems/Problem 3

Revision as of 07:19, 18 May 2016 by Quantummech (talk | contribs) (Solution)

Problem 3

Three primes $p,q$, and $r$ satisfy $p+q = r$ and $1 < p < q$. Then $p$ equals

$\textbf{(A)}\ 2\qquad \textbf{(B)}\ 3\qquad \textbf{(C)}\ 7\qquad \textbf{(D)}\ 13\qquad \textbf{(E)}\ 17$

Solution

We are given that $p,q$ and $r$ are primes. In order to sum two another prime, either $p$ or $q$ has to be even, because the sum of an odd and an even is odd. The only odd prime is $2$, and it is also the smallest prime, so therefore, the answer is $\fbox{\textbf{(A)}2}$.

See Also

1983 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions


The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png