Difference between revisions of "1983 AHSME Problems/Problem 5"

(Solution)
(Solution)
Line 8: Line 8:
 
B=(2,0);
 
B=(2,0);
 
C=(0,0);
 
C=(0,0);
pair A,B,C;
+
pair (A,B,C);
draw (A--B--C--A);
+
draw (A - - B - - C - - A);
 
</asy>
 
</asy>
  

Revision as of 07:27, 18 May 2016

Problem 5

Triangle $ABC$ has a right angle at $C$. If $\sin A = \frac{2}{3}$, then $\tan B$ is

$\textbf{(A)}\ \frac{3}{5}\qquad \textbf{(B)}\ \frac{\sqrt 5}{3}\qquad \textbf{(C)}\ \frac{2}{\sqrt 5}\qquad \text{(D)}\ \sqrt{3}\qquad \text{(E)}\ 2$

Solution

A=(0,1.7);
B=(2,0);
C=(0,0);
pair (A,B,C);
draw (A - - B - - C - - A);
 (Error making remote request. Unknown error_msg)

See Also

1983 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions


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