Difference between revisions of "1985 AHSME Problems/Problem 1"
(Created page with "==Problem 1== If <math> 2x+1=8 </math>, then <math> 4x+1= </math> <math> \mathrm{(A)\ } 15 \qquad \mathrm{(B) \ }16 \qquad \mathrm{(C) \ } 17 \qquad \mathrm{(D) \ } 18 \qquad...") |
m (→Problem 1) |
||
Line 1: | Line 1: | ||
− | ==Problem | + | ==Problem== |
If <math> 2x+1=8 </math>, then <math> 4x+1= </math> | If <math> 2x+1=8 </math>, then <math> 4x+1= </math> |
Revision as of 14:42, 26 May 2012
Problem
If , then
Solution
Solution 1
From , we subtract from both sides to get . We can divide both sides now by to get . Now we can substitute this into to get .
Solution 2
We proceed from as above. Notice that , so .
See Also
1985 AHSME (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |