Difference between revisions of "1985 AHSME Problems/Problem 1"
(Created page with "==Problem 1== If <math> 2x+1=8 </math>, then <math> 4x+1= </math> <math> \mathrm{(A)\ } 15 \qquad \mathrm{(B) \ }16 \qquad \mathrm{(C) \ } 17 \qquad \mathrm{(D) \ } 18 \qquad...") |
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| − | ==Problem | + | ==Problem== |
If <math> 2x+1=8 </math>, then <math> 4x+1= </math> | If <math> 2x+1=8 </math>, then <math> 4x+1= </math> | ||
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==See Also== | ==See Also== | ||
{{AHSME box|year=1985|before=First Problem|num-a=2}} | {{AHSME box|year=1985|before=First Problem|num-a=2}} | ||
| + | {{MAA Notice}} | ||
Revision as of 12:59, 5 July 2013
Problem
If 
, then 
Solution
Solution 1
From , we subtract 
from both sides to get 
. We can divide both sides now by 
to get 
. Now we can substitute this into 
to get 
.
Solution 2
We proceed from as above. Notice that 
, so 
.
See Also
| 1985 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
