1985 AJHSME Problem 1

Problem

$\frac{3\times 5}{9\times 11}\times \frac{7\times 9\times 11}{3\times 5\times 7}=$

$\text{(A)}\ 1 \qquad \text{(B)}\ 0 \qquad \text{(C)}\ 49 \qquad \text{(D)} \frac{1}{49}\ \qquad \text{(E)}\ 50$

Solution

$\frac{3\times 5}{9\times 11}\times \frac{7\times 9\times 11}{3\times 5\times 7}= \frac{3 \times 5 \times 7 \times 9 \times 11}{9 \times 11 \times 3 \times 5 \times 7} = \boxed{1}$

The answer is $\text{(A) 1}.$

Solution

the numeretor is 3*5*7*9*11, so is the denominator so (3*5*7*9*11)/(3*5*7*9*11)=1

-mathmax12

Video Solution

https://youtu.be/dszCk0HVWH8

~savannahsolver

1985 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 0	Followed by Problem 2
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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1985 AJHSME Problem 1

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Problem

Solution

Solution

Video Solution

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