1985 AJHSME Problems/Problem 2
We could just add them all together. But what would the point be of doing that? So we find a slicker way.
We find a simpler problem in this problem, and simplify ->
We know , that's easy - . So how do we find ?
Well once again (not once again if you didn't read the solution for #1), commutative property comes to the rescue. We rearrange the numbers to make . You might have noticed that each of the terms i put next to each other add up to 10, which make for easy adding. . Adding that on to 900 makes 945.
945 is (B)