Difference between revisions of "1986 AHSME Problems/Problem 1"
(Created page with "==Problem== <math>[x-(y-x)] - [(x-y) - x] =</math> <math>\textbf{(A)}\ 2y \qquad \textbf{(B)}\ 2x \qquad \textbf{(C)}\ -2y \qquad \textbf{(D)}\ -2x \qquad \textbf{(E)}\ 0 </mat...") |
(Fixed the problem statement and added a solution with explanation) |
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| Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
| − | <math>[x-(y- | + | <math>[x-(y-z)] - [(x-y) - z] =</math> |
<math>\textbf{(A)}\ 2y \qquad | <math>\textbf{(A)}\ 2y \qquad | ||
| − | \textbf{(B)}\ | + | \textbf{(B)}\ 2z \qquad |
\textbf{(C)}\ -2y \qquad | \textbf{(C)}\ -2y \qquad | ||
| − | \textbf{(D)}\ - | + | \textbf{(D)}\ -2z \qquad |
\textbf{(E)}\ 0 </math> | \textbf{(E)}\ 0 </math> | ||
==Solution== | ==Solution== | ||
| − | + | The expression becomes <math>(x-y+z)-(x-y-z) = x-y+z-x+y+z = 2z</math>, which is <math>\boxed{B}</math>. | |
== See also == | == See also == | ||
Latest revision as of 17:59, 1 April 2018
Problem
![$[x-(y-z)] - [(x-y) - z] =$](http://latex.artofproblemsolving.com/9/7/b/97b1585ca65be41e61989680b4171c3197eb8fa8.png)
Solution
The expression becomes 
, which is 
.
See also
| 1986 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
