Difference between revisions of "1986 AHSME Problems/Problem 11"
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==Solution== | ==Solution== | ||
− | In a right triangle, the length of the hypotenuse is twice the length of the median which bisects it. If the hypotenuse is <math>13</math>, the | + | In a right triangle, the length of the hypotenuse is twice the length of the median which bisects it. If the hypotenuse is <math>13</math>, the median must be <math>6.5</math>. |
== See also == | == See also == |
Revision as of 18:57, 1 August 2017
Problem
In and . Also, is the midpoint of side and is the foot of the altitude from to . The length of is
Solution
In a right triangle, the length of the hypotenuse is twice the length of the median which bisects it. If the hypotenuse is , the median must be .
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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