Difference between revisions of "1986 AHSME Problems/Problem 14"
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==Solution== | ==Solution== | ||
− | + | <math>1</math> metre equals <math>\frac{f}{g}</math> jumps, which is <math>\frac{f}{g} \frac{e}{d}</math> hops, and then <math>\frac{f}{g} \frac{e}{d} \frac{c}{b}</math> skips, which becomes <math>\frac{cef}{bdg}</math>, i.e. answer <math>\boxed{D}</math>. | |
== See also == | == See also == |
Latest revision as of 17:36, 1 April 2018
Problem
Suppose hops, skips and jumps are specific units of length. If hops equals skips, jumps equals hops, and jumps equals meters, then one meter equals how many skips?
Solution
metre equals jumps, which is hops, and then skips, which becomes , i.e. answer .
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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All AHSME Problems and Solutions |
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