Difference between revisions of "1986 AJHSME Problems/Problem 14"
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==Solution== | ==Solution== | ||
− | + | <math>\frac{b}{a}</math> will be largest if <math>b</math> is the largest it can be, and <math>a</math> is the smallest it can be. | |
Since <math>b</math> can be no larger than <math>1200</math>, <math>b = 1200</math>. Since <math>a</math> can be no less than <math>200</math>, <math>a = 200</math>. <math>\frac{1200}{200} = 6</math> | Since <math>b</math> can be no larger than <math>1200</math>, <math>b = 1200</math>. Since <math>a</math> can be no less than <math>200</math>, <math>a = 200</math>. <math>\frac{1200}{200} = 6</math> | ||
− | 6 is C | + | <math>6</math> is <math>\boxed{\text{C}}</math> |
==See Also== | ==See Also== | ||
− | [[ | + | {{AJHSME box|year=1986|num-b=13|num-a=15}} |
+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 21:17, 3 July 2013
Problem
If and , then the largest value of the quotient is
Solution
will be largest if is the largest it can be, and is the smallest it can be.
Since can be no larger than , . Since can be no less than , .
is
See Also
1986 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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