Difference between revisions of "1986 AJHSME Problems/Problem 3"
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==Problem== | ==Problem== | ||
− | The smallest sum one could get by adding three different numbers from the set <math>\{ 7,25,-1,12,-3 \}</math> is | + | The smallest [[sum]] one could get by adding three different numbers from the [[set]] <math>\{ 7,25,-1,12,-3 \}</math> is |
<math>\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21</math> | <math>\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21</math> | ||
Line 15: | Line 15: | ||
==See Also== | ==See Also== | ||
− | [[ | + | {{AJHSME box|year=1986|num-b=2|num-a=4}} |
+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 20:06, 3 July 2013
Problem
The smallest sum one could get by adding three different numbers from the set is
Solution
To find the smallest sum, we just have to find the smallest 3 numbers and add them together.
Obviously, the numbers are , and adding them gets us .
See Also
1986 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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