Difference between revisions of "1986 AJHSME Problems/Problem 3"

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Obviously, the numbers are <math>-3, -1, 7</math>, and adding them gets us <math>3</math>.
 
Obviously, the numbers are <math>-3, -1, 7</math>, and adding them gets us <math>3</math>.
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 +
<math>\boxed{\text{C}}</math>
  
 
==See Also==
 
==See Also==
  
 
[[1986 AJHSME Problems]]
 
[[1986 AJHSME Problems]]

Revision as of 17:57, 20 January 2009

Problem

The smallest sum one could get by adding three different numbers from the set $\{ 7,25,-1,12,-3 \}$ is

$\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21$

Solution

To find the smallest sum, we just have to find the smallest 3 numbers and add them together.

Obviously, the numbers are $-3, -1, 7$, and adding them gets us $3$.

$\boxed{\text{C}}$

See Also

1986 AJHSME Problems

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