Difference between revisions of "1986 AJHSME Problems/Problem 6"
5849206328x (talk | contribs) (New page: ==Problem== <math>\frac{2}{1-\frac{2}{3}}=</math> <math>\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6</math> ==...) |
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==Solution== | ==Solution== | ||
| − | {{ | + | A rather simple problem, if you have a basic understanding of fractions. |
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| + | Just simplify the bottom, getting us <math>\frac{2}{\frac{1}{3}}</math>, with which we multiply both sides by 3, getting us <math>\frac{6}{1}</math>, or <math>6</math> | ||
==See Also== | ==See Also== | ||
[[1986 AJHSME Problems]] | [[1986 AJHSME Problems]] | ||
Revision as of 23:24, 23 January 2009
Problem
Solution
A rather simple problem, if you have a basic understanding of fractions.
Just simplify the bottom, getting us 
, with which we multiply both sides by 3, getting us 
, or 
