1986 AJHSME Problems/Problem 6

Revision as of 09:09, 19 January 2009 by 5849206328x (talk | contribs) (New page: ==Problem== <math>\frac{2}{1-\frac{2}{3}}=</math> <math>\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6</math> ==...)
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Problem

$\frac{2}{1-\frac{2}{3}}=$

$\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6$

Solution

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See Also

1986 AJHSME Problems