Difference between revisions of "1987 AHSME Problems/Problem 7"

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\textbf{(E)}\ \text{no one is always largest}</math>     
 
\textbf{(E)}\ \text{no one is always largest}</math>     
  
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== Solution ==
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We have <math>a = a</math>, <math>b = a - 3</math>, <math>c = a + 2</math>, and <math>d = a - 5</math>, so now as <math>2 > 0 > -3 > -5</math>, <math>c</math> is always largest. Hence the answer is <math>\boxed{\text{C}}</math>.
  
 
== See also ==
 
== See also ==

Latest revision as of 14:00, 1 March 2018

Problem

If $a-1=b+2=c-3=d+4$, which of the four quantities $a,b,c,d$ is the largest?

$\textbf{(A)}\ a \qquad \textbf{(B)}\ b \qquad \textbf{(C)}\ c \qquad \textbf{(D)}\ d \qquad \textbf{(E)}\ \text{no one is always largest}$

Solution

We have $a = a$, $b = a - 3$, $c = a + 2$, and $d = a - 5$, so now as $2 > 0 > -3 > -5$, $c$ is always largest. Hence the answer is $\boxed{\text{C}}$.

See also

1987 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
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