Difference between revisions of "1987 AJHSME Problems/Problem 2"

(New page: ==Problem== <math>\frac{2}{25}=</math> <math>\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)} 1.25 \qquad \text{(E)}\ 12.5</math> ==Solution== {{Solution...)
 
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==Solution==
 
==Solution==
  
{{Solution}}
+
<math>\frac{2}{25}=\frac{2\cdot 4}{25\cdot 4} = \frac{8}{100} = \boxed{0.08}</math>
  
 
==See Also==
 
==See Also==
  
 
[[1987 AJHSME Problems]]
 
[[1987 AJHSME Problems]]

Revision as of 14:49, 29 January 2009

Problem

$\frac{2}{25}=$

$\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)} 1.25 \qquad \text{(E)}\ 12.5$

Solution

$\frac{2}{25}=\frac{2\cdot 4}{25\cdot 4} = \frac{8}{100} = \boxed{0.08}$

See Also

1987 AJHSME Problems

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