Difference between revisions of "1987 AJHSME Problems/Problem 4"
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==Solution== | ==Solution== | ||
− | The right angle is <math>1/4</math> of the circle, hence it contains <math>500/4=\boxed{ | + | The right angle is <math>1/4</math> of the circle, hence it contains <math>500/4=125\rightarrow \boxed{\text{C}}</math> clerts. |
==See Also== | ==See Also== | ||
− | [[ | + | {{AJHSME box|year=1987|num-b=3|num-a=5}} |
+ | [[Category:Introductory Geometry Problems]] | ||
+ | {{MAA Notice}} |
Revision as of 23:52, 4 July 2013
Problems
Martians measure angles in clerts. There are clerts in a full circle. How many clerts are there in a right angle?
Solution
The right angle is of the circle, hence it contains clerts.
See Also
1987 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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