Difference between revisions of "1988 AHSME Problems/Problem 1"

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==Problem==
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<math> \sqrt{8}+\sqrt{18}= </math>
 
<math> \sqrt{8}+\sqrt{18}= </math>
  
 
<cmath> \text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13} </cmath>
 
<cmath> \text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13} </cmath>
  
Solution<math> \sqrt{8} = 2 * \sqrt{2} </math>
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==Solution==
              <math> \sqrt{18} = 3 * \sqrt{2} </math>
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<math> \sqrt{8} = 2 \sqrt{2} </math>
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<math> \sqrt{18} = 3 \sqrt{2} </math>
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So adding the two terms we get <math> 2  \sqrt{2} + 3  \sqrt{2} = 5  \sqrt{2} </math> , which corresponds to answer choice <math>\boxed{\textbf{(D)}}</math> .
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== See also ==
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{{AHSME box|year=1988|before=First Question|num-a=2}} 
  
So adding the two terms we get <math> 2 * \sqrt{2} + 3 * \sqrt{2} = 5 * \sqrt{2} </math> , which corresponds to answer choice \text{(D)} .
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[[Category: Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 01:42, 23 October 2014

Problem

$\sqrt{8}+\sqrt{18}=$

\[\text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13}\]

Solution

$\sqrt{8} = 2  \sqrt{2}$

$\sqrt{18} = 3  \sqrt{2}$

So adding the two terms we get $2  \sqrt{2} + 3  \sqrt{2} = 5  \sqrt{2}$ , which corresponds to answer choice $\boxed{\textbf{(D)}}$ .


See also

1988 AHSME (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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