Difference between revisions of "1988 AJHSME Problems/Problem 10"

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<math>\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text{Wednesday} \qquad \text{(C)}\ \text{Thursday} \qquad \text{(D)}\ \text{Friday} \qquad \text{(E)}\ \text{Saturday}</math>
 
<math>\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text{Wednesday} \qquad \text{(C)}\ \text{Thursday} \qquad \text{(D)}\ \text{Friday} \qquad \text{(E)}\ \text{Saturday}</math>
  
==Solution==
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==Solutions==
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===Solution 1===
 
7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a <math>\text{Monday} \Rightarrow \mathrm{(A)}</math>.
 
7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a <math>\text{Monday} \Rightarrow \mathrm{(A)}</math>.
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===Solution 2===
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Note that <math>60\equiv4\pmod7</math>.  We count 4 days past Thursday, and arrive at Monday. <math> \mathrm{(A)}</math>
  
 
==See Also==
 
==See Also==

Revision as of 11:36, 20 August 2011

Problem

Chris' birthday is on a Thursday this year. What day of the week will it be $60$ days after her birthday?

$\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text{Wednesday} \qquad \text{(C)}\ \text{Thursday} \qquad \text{(D)}\ \text{Friday} \qquad \text{(E)}\ \text{Saturday}$

Solutions

Solution 1

7 days after her birthday would be a Thursday, as would 14, 21, 28, 35, 42, 49, and 56. Therefore the 60th would be four days after a Thursday, which is a $\text{Monday} \Rightarrow \mathrm{(A)}$.

Solution 2

Note that $60\equiv4\pmod7$. We count 4 days past Thursday, and arrive at Monday. $\mathrm{(A)}$

See Also

1988 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions