Difference between revisions of "1988 AJHSME Problems/Problem 2"
5849206328x (talk | contribs) (New page: ==Problem== The product <math>8\times .25\times 2\times .125 =</math> <math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E...) |
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==Problem== | ==Problem== | ||
| − | The product <math>8\times .25\times 2\times .125 =</math> | + | The [[product]] <math>8\times .25\times 2\times .125 =</math> |
<math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math> | <math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math> | ||
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==Solution== | ==Solution== | ||
| − | Converting the decimals to fractions, this is | + | Converting the [[Decimal|decimals]] to [[Fraction|fractions]], this is |
<cmath>\begin{align*} | <cmath>\begin{align*} | ||
8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\ | 8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\ | ||
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==See Also== | ==See Also== | ||
| − | [[ | + | {{AJHSME box|year=1988|num-b=1|num-a=3}} |
| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 23:54, 4 July 2013
Problem
The product 
Solution
Converting the decimals to fractions, this is
See Also
| 1988 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
