Difference between revisions of "1989 AHSME Problems/Problem 1"

(Created page with "(-1)^(5^2) + 1^(2^5) = (A) -7 (B) -2 (C) 0 (D) 1 (E) 57")
 
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(-1)^(5^2) + 1^(2^5) =  
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<math>(-1)^{5^2} + 1^{2^5} = (-1)^{25}+1^{32}=-1+1=0</math> thus the answer is C.
 
 
(A) -7    (B) -2    (C) 0    (D) 1    (E) 57
 

Revision as of 09:54, 19 February 2012

$(-1)^{5^2} + 1^{2^5} = (-1)^{25}+1^{32}=-1+1=0$ thus the answer is C.