Difference between revisions of "1989 AHSME Problems/Problem 15"
m |
|||
Line 1: | Line 1: | ||
− | + | == Problem == | |
+ | |||
+ | In <math>\triangle ABC</math>, <math>AB=5</math>, <math>BC=7</math>, <math>AC=9</math>, and <math>D</math> is on <math>\overline{AC}</math> with <math>BD=5</math>. Find the ratio of <math>AD:DC</math>. | ||
+ | |||
+ | <asy> | ||
+ | draw((3,4)--(0,0)--(9,0)--(3,4)--(6,0)); | ||
+ | dot((0,0)); | ||
+ | dot((9,0)); | ||
+ | dot((3,4)); | ||
+ | dot((6,0)); | ||
+ | label("A", (0,0), W); | ||
+ | label("B", (3,4), N); | ||
+ | label("C", (9,0), E); | ||
+ | label("D", (6,0), S);</asy> | ||
+ | |||
+ | <math> \textrm{(A)}\ 4:3\qquad\textrm{(B)}\ 7:5\qquad\textrm{(C)}\ 11:6\qquad\textrm{(D)}\ 13:5\qquad\textrm{(E)}\ 19:8 </math> | ||
+ | |||
+ | == Solution == | ||
+ | |||
+ | == See also == | ||
+ | {{AHSME box|year=1989|num-b=14|num-a=16}} | ||
+ | |||
+ | [[Category: Introductory Geometry Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 06:53, 22 October 2014
Problem
In , , , , and is on with . Find the ratio of .
Solution
See also
1989 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.