Difference between revisions of "1989 AHSME Problems/Problem 17"
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The perimeter of an equilateral triangle exceeds the perimeter of a square by <math>1989 \ \text{cm}</math>. The length of each side of the triangle exceeds the length of each side of the square by <math>d \ \text{cm}</math>. The square has perimeter greater than 0. How many positive integers are NOT possible value for <math>d</math>? | The perimeter of an equilateral triangle exceeds the perimeter of a square by <math>1989 \ \text{cm}</math>. The length of each side of the triangle exceeds the length of each side of the square by <math>d \ \text{cm}</math>. The square has perimeter greater than 0. How many positive integers are NOT possible value for <math>d</math>? | ||
| − | <math>\text{(A)} \ 0 \qquad \text{(B)} \ 9 \qquad \text{(C)} \ 221 \qquad \text{(D)} \ 663 \qquad \text{(E)} \ \ | + | <math>\text{(A)} \ 0 \qquad \text{(B)} \ 9 \qquad \text{(C)} \ 221 \qquad \text{(D)} \ 663 \qquad \text{(E)} \ \infty </math> |
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| + | == Solution == | ||
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| + | == See also == | ||
| + | {{AHSME box|year=1989|num-b=16|num-a=18}} | ||
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| + | [[Category: Introductory Geometry Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 07:55, 22 October 2014
Problem
The perimeter of an equilateral triangle exceeds the perimeter of a square by 
. The length of each side of the triangle exceeds the length of each side of the square by 
. The square has perimeter greater than 0. How many positive integers are NOT possible value for 
?
Solution
See also
| 1989 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 16 |
Followed by Problem 18 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
