1989 AIME Problems/Problem 1

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Problem

Compute $\sqrt{(31)(30)(29)(28)+1}$.

Solution

Let's call our four consecutive integers $(n-1), n, (n+1), (n+2)$. Notice that $(n-1)(n)(n+1)(n+2)+1=(n^2+n)^2-2(n^2+n)+1 \Rightarrow (n^2+n-1)^2$. Thus, $\sqrt{(31)(30)(29)(28)+1} = (29^2+29-1) = 869$

See also