1989 AJHSME Problems/Problem 13

Revision as of 19:51, 7 June 2009 by 5849206328x (talk | contribs) (New page: ==Problem== <math>\frac{9}{7\times 53} =</math> <math>\text{(A)}\ \frac{.9}{.7\times 53} \qquad \text{(B)}\ \frac{.9}{.7\times .53} \qquad \text{(C)}\ \frac{.9}{.7\times 5.3} \qquad \tex...)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

$\frac{9}{7\times 53} =$

$\text{(A)}\ \frac{.9}{.7\times 53} \qquad \text{(B)}\ \frac{.9}{.7\times .53} \qquad \text{(C)}\ \frac{.9}{.7\times 5.3} \qquad \text{(D)}\ \frac{.9}{7\times .53} \qquad \text{(E)}\ \frac{.09}{.07\times .53}$

Solution

\begin{align*} \frac{9}{7\times 53} &= \frac{.9\times 10}{.7\times 10\times 53} \\ &= \frac{.9}{.7\times 53} \rightarrow \boxed{\text{A}} \end{align*}

See Also

1989 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions