Difference between revisions of "1990 AHSME Problems/Problem 15"

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== Solution ==
 
== Solution ==
<math>\fbox{C}</math>
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Let <math>S</math> be the sum of the four numbers. Then <math>180+197+208+222=807=3S\therefore S=269</math>, and subtracting <math>180</math> gives <math>89</math> for <math>\fbox{C}</math>
  
 
== See also ==
 
== See also ==

Latest revision as of 05:37, 4 February 2016

Problem

Four whole numbers, when added three at a time, give the sums $180,197,208$ and $222$. What is the largest of the four numbers?

$\text{(A) } 77\quad \text{(B) } 83\quad \text{(C) } 89\quad \text{(D) } 95\quad \text{(E) cannot be determined from the given information}$

Solution

Let $S$ be the sum of the four numbers. Then $180+197+208+222=807=3S\therefore S=269$, and subtracting $180$ gives $89$ for $\fbox{C}$

See also

1990 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
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