Difference between revisions of "1990 AHSME Problems/Problem 20"
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== Problem == | == Problem == | ||
<asy> | <asy> | ||
− | + | pair A = (0,0), B = (7,4.2), C = (10, 0), D = (3, -5), E = (3, 0), F = (7,0); | |
− | + | draw(A--B--C--D--cycle,dot); | |
− | draw( | + | draw(A--E--F--C,dot); |
− | draw( | + | draw(D--E--F--B,dot); |
− | draw( | + | markscalefactor = 0.1; |
− | draw(( | + | draw(rightanglemark(B, A, D)); |
− | draw(( | + | draw(rightanglemark(D, E, C)); |
− | MP("A",(0,0),W);MP("B",(7,4.2),N);MP("C",(10,0),E);MP("D",(3,-5),S);MP("E",(3,0),N);MP("F",(7,0),S); | + | draw(rightanglemark(B, F, A)); |
+ | draw(rightanglemark(D, C, B)); | ||
+ | MP("A",(0,0),W); | ||
+ | MP("B",(7,4.2),N); | ||
+ | MP("C",(10,0),E); | ||
+ | MP("D",(3,-5),S); | ||
+ | MP("E",(3,0),N); | ||
+ | MP("F",(7,0),S); | ||
</asy> | </asy> | ||
Revision as of 12:26, 22 February 2018
Problem
In the figure is a quadrilateral with right angles at and . Points and are on , and and are perpendicual to . If and , then
Solution
See also
1990 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.