Difference between revisions of "1990 AIME Problems/Problem 8"
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== Problem == | == Problem == | ||
| + | In a shooting match, eight clay targets are arranged in two hanging columns of three targets each and one column of two targets. A marksman is to break all the targets according to the following rules: | ||
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| + | 1) The marksman first chooses a column from which a target is to be broken. | ||
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| + | 2) The marksman must then break the lowest remaining target in the chosen column. | ||
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| + | If the rules are followed, in how many different orders can the eight targets be broken? | ||
== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=1990|num-b=7|num-a=9}} | |
Revision as of 01:27, 2 March 2007
Problem
In a shooting match, eight clay targets are arranged in two hanging columns of three targets each and one column of two targets. A marksman is to break all the targets according to the following rules:
1) The marksman first chooses a column from which a target is to be broken.
2) The marksman must then break the lowest remaining target in the chosen column.
If the rules are followed, in how many different orders can the eight targets be broken?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 1990 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
