Difference between revisions of "1990 AJHSME Problems/Problem 10"

Revision as of 16:41, 31 July 2019

Solution

Looking at the positions of the letters, we see that if the date behind $\text{Q}$ is $q$ , then the date behind $\textbf{A}$ is $q-6$ and the date behind $\textbf{B}$ is $q+6$ . Thus, their sum is $2q$ .

The date behind $\text{C}$ is $q-7$ , so the desired letter is the one for which the date behind it is $2q-(q-7)=q+7$ . This is letter $\text{P}\rightarrow \boxed{\text{A}}$ .

1990 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 9	Followed by Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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-==Problem==
-On this monthly calendar, the date ahead of  one of the letters is added to the date behind <math>\text{C}</math>.  If this sum equals the sum of the dates behind <math>\text{A}</math> and <math>\text{B}</math>, then the ria is the stupido an rohan likes to give her a tight slap on her stupido face which you need sunglasses to look at or else you will turn blind
 ==Solution==

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Difference between revisions of "1990 AJHSME Problems/Problem 10"

Revision as of 16:41, 31 July 2019

Solution

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