Difference between revisions of "1990 AJHSME Problems/Problem 13"
5849206328x (talk | contribs) (Created page with '==Problem== One proposal for new postage rates for a letter was <math>30</math> cents for the first ounce and <math>22</math> cents for each additional ounce (or fraction of an …') |
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==Solution== | ==Solution== | ||
− | After the first ounce, there are <math>3.5</math> ounces left. | + | After the first ounce, there are <math>3.5</math> ounces left. Since each additional ounce or fraction of an ounce adds <math>22</math> cents to the total cost, we need to add <math>4\times 22</math> to the cost for the first ounce. |
− | + | So, the total price is <math>30+4\times 22=118</math> cents. The answer is choice <math>\boxed{\textbf{(C)}~\mathbf{1.18}~\textbf{dollars}}</math>. | |
==See Also== | ==See Also== | ||
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{{AJHSME box|year=1990|num-b=12|num-a=14}} | {{AJHSME box|year=1990|num-b=12|num-a=14}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 18:01, 8 August 2018
Problem
One proposal for new postage rates for a letter was cents for the first ounce and cents for each additional ounce (or fraction of an ounce). The postage for a letter weighing ounces was
Solution
After the first ounce, there are ounces left. Since each additional ounce or fraction of an ounce adds cents to the total cost, we need to add to the cost for the first ounce.
So, the total price is cents. The answer is choice .
See Also
1990 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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