Difference between revisions of "1992 AHSME Problems/Problem 2"

m (Added period at the end of a sentence)
(Solution)
Line 10: Line 10:
  
 
== Solution ==
 
== Solution ==
If twenty percent of the objects in the urn are beads, then the other 80% of the objects must be coins. Since 40% of the coins are silver, then 60% of the coins must be gold. Therefore, 60% of 80% of the objects in the urn are gold coins. Since <math>.6\times.8=.48</math>, 48 percent of the objects in the urn must be gold coins. Thus the answer is <math>\fbox{B}</math>.
+
If twenty percent of the objects in the urn are beads, then the other <math>80%</math> of the objects must be coins. Since <math>40%</math> of the coins are silver, then <math>60%</math> of the coins must be gold. Therefore, <math>60%</math> of <math>80%</math> of the objects in the urn are gold coins. Since <math>.6\times.8=.48</math>, 48 percent of the objects in the urn must be gold coins. Thus the answer is <math>\fbox{B}</math>.
  
 
== See also ==
 
== See also ==

Revision as of 14:52, 17 October 2021

Problem

An urn is filled with coins and beads, all of which are either silver or gold. Twenty percent of the objects in the urn are beads. Forty percent of the coins in the urn are silver. What percent of objects in the urn are gold coins?

$\text{(A) } 40\%\quad \text{(B) } 48\%\quad \text{(C) } 52\%\quad \text{(D) } 60\%\quad \text{(E) } 80\%$

Solution

If twenty percent of the objects in the urn are beads, then the other $80%$ (Error compiling LaTeX. Unknown error_msg) of the objects must be coins. Since $40%$ (Error compiling LaTeX. Unknown error_msg) of the coins are silver, then $60%$ (Error compiling LaTeX. Unknown error_msg) of the coins must be gold. Therefore, $60%$ (Error compiling LaTeX. Unknown error_msg) of $80%$ (Error compiling LaTeX. Unknown error_msg) of the objects in the urn are gold coins. Since $.6\times.8=.48$, 48 percent of the objects in the urn must be gold coins. Thus the answer is $\fbox{B}$.

See also

1992 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png