Difference between revisions of "1992 AHSME Problems/Problem 5"

(Solution)
(Solution)
 
Line 10: Line 10:
  
 
== Solution ==
 
== Solution ==
We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\textbf{(B) }6^7</math>.
+
We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}</math>.
  
 
== See also ==
 
== See also ==

Latest revision as of 16:21, 5 August 2016

Problem

$6^6+6^6+6^6+6^6+6^6+6^6=$

$\text{(A) } 6^6 \quad \text{(B) } 6^7\quad \text{(C) } 36^6\quad \text{(D) } 6^{36}\quad \text{(E) } 36^{36}$

Solution

We notice that $6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}$.

See also

1992 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png