1992 AIME Problems/Problem 3

Problem

A tennis player computes her win ratio by dividing the number of matches she has won by the total number of matches she has played. At the start of a weekend, her win ratio is exactly $\displaystyle.500$ . During the weekend, she plays four matches, winning three and losing one. At the end of the weekend, her win ratio is greater than $\displaystyle .503$ . What's the largest number of matches she could've won before the weekend began?

Solution

Let $\displaystyle n$ be the number of matches won, so that $\displaystyle \frac{n}{2n}=\frac{1}{2}$ , and $\displaystyle \frac{n+3}{2n+4}>\frac{503}{1000}$ . Cross multiplying, $\displaystyle 1000n+3000>1006n+2012$ , and $\displaystyle n<\frac{988}{6}$ . Thus, the answer is $\displaystyle 164$ .

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1992 AIME Problems/Problem 3

Problem

Solution

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