Difference between revisions of "1992 AJHSME Problems/Problem 18"

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==Solution==
 
==Solution==
 
The average speed is given by the total distance traveled divided by the total time traveled.
 
The average speed is given by the total distance traveled divided by the total time traveled.
<cmath>\frac{80+0+100}{4} = \boxed{\text{(A)}\ 45}</cmath>
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<cmath>\frac{80+0+100}{4} = \boxed{\text{(\textbf{A})}\ 45}</cmath>
  
 
==See Also==
 
==See Also==
 
{{AJHSME box|year=1992|num-b=17|num-a=19}}
 
{{AJHSME box|year=1992|num-b=17|num-a=19}}
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{{MAA Notice}}

Latest revision as of 05:42, 31 August 2015

Problem

On a trip, a car traveled $80$ miles in an hour and a half, then was stopped in traffic for $30$ minutes, then traveled $100$ miles during the next $2$ hours. What was the car's average speed in miles per hour for the $4$-hour trip?

$\text{(A)}\ 45 \qquad \text{(B)}\ 50 \qquad \text{(C)}\ 60 \qquad \text{(D)}\ 75 \qquad \text{(E)}\ 90$

Solution

The average speed is given by the total distance traveled divided by the total time traveled. \[\frac{80+0+100}{4} = \boxed{\text{(\textbf{A})}\ 45}\]

See Also

1992 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 17
Followed by
Problem 19
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All AJHSME/AMC 8 Problems and Solutions

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