1992 AJHSME Problems/Problem 8

Revision as of 16:29, 29 July 2011 by Math Kirby (talk | contribs)

Problem

A store owner bought $1500$ pencils at <dollar/>0.10 each. If he sells them for <dollar/>0.25 each, how many of them must he sell to make a profit of exactly <dollar/>100.00?

$\text{(A)}\ 400 \qquad \text{(B)}\ 667 \qquad \text{(C)}\ 1000 \qquad \text{(D)}\ 1500 \qquad \text{(E)}\ 1900$

Solution

$1500\times 0.1=150$, so the store owner is <dollar/>150 below profit. Therefore he needs to sell 150+100=<dollar/>250 worth of pencils. Selling them at <dollar/>0.25 each gives 250/0.25=1000 which is choice C.