Difference between revisions of "1993 AHSME Problems/Problem 16"
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== Solution == | == Solution == | ||
+ | You want to find the largest integer x that satisfies <math>\frac{x*(x+1)}{2}<1993</math>. | ||
+ | You then can find that value of x, which is <math>62</math>. Therefore, the next value of the sequence is <math>63</math>. | ||
+ | <math>63/5</math> has a remainder of <math>3</math>. | ||
<math>\fbox{D}</math> | <math>\fbox{D}</math> | ||
Revision as of 15:41, 3 August 2019
Problem
Consider the non-decreasing sequence of positive integers in which the positive integer appears times. The remainder when the term is divided by is
Solution
You want to find the largest integer x that satisfies . You then can find that value of x, which is . Therefore, the next value of the sequence is . has a remainder of .
See also
1993 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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