Difference between revisions of "1993 AIME Problems/Problem 3"
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== Solution == | == Solution == | ||
− | Suppose that the number of fish is <math>x</math> and the number of contestants is <math>y</math>. The <math>y-21</math> fishers that caught <math>3</math> or more fish caught a total of <math>x - \left(0(9) + 1(5) + 2(7)\right) = x - 19</math> fish. Since they averaged <math>6</math> fish, <center><math>6 = \frac{x - 19}{y - 21} \Longrightarrow x - 19 = 6y - 126.</math></center> Similarily, those whom caught <math>12</math> or fewer fish averaged <math>5</math> fish per person, so <center><math>5 = \frac{x - (13(5) + 14(2) + 15(1))}{y - 8} = \frac{x - 108}{y - 8} \Longrightarrow x - 108 = 5y - 40.</math></center> Solving the two equation system, we find that <math>y = 175</math> and <math>x = \boxed{943}</math>, the answer. | + | Suppose that the number of fish is <math>x</math> and the number of contestants is <math>y</math>. The <math>y-(9+5+7)=y-21</math> fishers that caught <math>3</math> or more fish caught a total of <math>x - \left(0\cdot(9) + 1\cdot(5) + 2\cdot(7)\right) = x - 19</math> fish. Since they averaged <math>6</math> fish, <center><math>6 = \frac{x - 19}{y - 21} \Longrightarrow x - 19 = 6y - 126.</math></center> Similarily, those whom caught <math>12</math> or fewer fish averaged <math>5</math> fish per person, so <center><math>5 = \frac{x - (13(5) + 14(2) + 15(1))}{y - 8} = \frac{x - 108}{y - 8} \Longrightarrow x - 108 = 5y - 40.</math></center> Solving the two equation system, we find that <math>y = 175</math> and <math>x = \boxed{943}</math>, the answer. |
== See also == | == See also == |
Latest revision as of 02:50, 5 March 2021
Problem
The table below displays some of the results of last summer's Frostbite Falls Fishing Festival, showing how many contestants caught fish for various values of .
In the newspaper story covering the event, it was reported that
- (a) the winner caught fish;
- (b) those who caught or more fish averaged fish each;
- (c) those who caught or fewer fish averaged fish each.
What was the total number of fish caught during the festival?
Solution
Suppose that the number of fish is and the number of contestants is . The fishers that caught or more fish caught a total of fish. Since they averaged fish,
Similarily, those whom caught or fewer fish averaged fish per person, so
Solving the two equation system, we find that and , the answer.
See also
1993 AIME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.