Difference between revisions of "1993 AJHSME Problems/Problem 24"
Line 18: | Line 18: | ||
==See Also== | ==See Also== | ||
{{AJHSME box|year=1993|num-b=23|num-a=25}} | {{AJHSME box|year=1993|num-b=23|num-a=25}} | ||
+ | {{MAA Notice}} |
Revision as of 23:12, 4 July 2013
Problem
What number is directly above in this array of numbers?
\[\begin{tabular}{cccccc}& & & 1 & &\\ & & 2 & 3 & 4 &\\ & 5 & 6 & 7 & 8 & 9\\ 10 & 11 & 12 &\cdots & &\\ \end{tabular}\] (Error compiling LaTeX. ! Missing $ inserted.)
Solution
Solution 1
Notice that a number in row is less than the number directly below it. For example, , which is in row , is less than the number below it, .
From row 1 to row , there are numbers in those rows. Because there are numbers up to the 12th row, is in the row. The number directly above is in the 11th row, and is less than . Thus the number directly above is .
Solution 2
Writing a couple more rows, the last number in each row ends in a perfect square. Thus is two left from the last number in its row, . One left and one up from is the last number of its row, also a perfect square, and is . This is one right and one up from , so the number directly above is one less than , or .
See Also
1993 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.