1993 AJHSME Problems/Problem 7

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Problem 7

$3^3+3^3+3^3 =$

$\text{(A)}\ 3^4 \qquad \text{(B)}\ 9^3 \qquad \text{(C)}\ 3^9 \qquad \text{(D)}\ 27^3 \qquad \text{(E)}\ 3^{27}$

Solution

$3^3+3^3+3^3 = 3 \times 3^3 = \boxed{\text{(A)}\ 3^4}$

See Also

1993 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
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All AJHSME/AMC 8 Problems and Solutions