Difference between revisions of "1994 AJHSME Problems/Problem 3"
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8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math> | 8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math> | ||
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| + | ==The Hacker== | ||
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==See Also== | ==See Also== | ||
{{AJHSME box|year=1994|num-b=2|num-a=4}} | {{AJHSME box|year=1994|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 23:36, 27 October 2016
Contents
Problem
Each day Maria must work 
hours(LOL). This does not include the 
minutes(People just buy a sandwich and eat at their desks these days) she takes for lunch. If she begins working at 
and takes her lunch break at noon(you mean lunch time), then her working day will end at night.
Solution
8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at 
The Hacker
See Also
| 1994 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
