Difference between revisions of "1994 AJHSME Problems/Problem 3"

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8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math>
 
8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math>
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==The Hacker==
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==See Also==
 
==See Also==
 
{{AJHSME box|year=1994|num-b=2|num-a=4}}
 
{{AJHSME box|year=1994|num-b=2|num-a=4}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:36, 27 October 2016

Problem

Each day Maria must work $8$ hours(LOL). This does not include the $45$ minutes(People just buy a sandwich and eat at their desks these days) she takes for lunch. If she begins working at $\text{7:25 A.M.}$ and takes her lunch break at noon(you mean lunch time), then her working day will end at night.

$\text{(A)}\ \text{3:40 P.M.} \qquad \text{(B)}\ \text{3:55 P.M.} \qquad \text{(C)}\ \text{4:10 P.M.} \qquad \text{(D)}\ \text{4:25 P.M.} \qquad \text{(E)}\ \text{4:40 P.M.}$

Solution

8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at $\boxed{\text{(C)}\ \text{4:10 P.M.}}$


The Hacker

See Also

1994 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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