Difference between revisions of "1994 AJHSME Problems/Problem 5"
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Latest revision as of 00:13, 5 July 2013
Problem
Given that 
and 
, the number of rods in one mile is
Solution
![\[(1\ \text{mile}) \left( \frac{8\ \text{furlongs}}{1\ \text{mile}} \right) \left( \frac{40\ \text{rods}}{1\ \text{furlong}} \right) = \boxed{\text{(B)}\ 320}\]](http://latex.artofproblemsolving.com/e/a/0/ea00765750fa695fb2636a3a5d8164c34ae313c0.png)
See Also
| 1994 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
