Difference between revisions of "1995 AJHSME Problems/Problem 2"

m (Test)
Line 12: Line 12:
  
 
==See Also==
 
==See Also==
{{AJHSME box|year=1995|num-b=1|num-a=3}}
+
{{AJHSME box|year=1995|num-b=2|num-a=3}}
 
* [[AJHSME]]
 
* [[AJHSME]]
 
* [[AJHSME Problems and Solutions]]
 
* [[AJHSME Problems and Solutions]]
 
* [[Mathematics competition resources]]
 
* [[Mathematics competition resources]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 21:04, 27 October 2016

Problem

Jose is $4$ years younger than Zack. Zack is $3$ years older than Inez. Inez is $15$ years old. How old is Jose?

$\text{(A)}\ 8 \qquad \text{(B)}\ 11 \qquad \text{(C)}\ 14 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 22$

Solution

Zack is $3$ years older than Inez, who is $15$. Therefore, Zack is $15 + 3 = 18$ years old.

Jose is $4$ years younger than Zack, who is $18$. Therefore, Jose is $18 - 4 = 14$ years old, and the answer is $\boxed{C}$.

See Also

1995 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png