Difference between revisions of "1997 AJHSME Problems/Problem 7"
Talkinaway (talk | contribs) |
|||
| Line 14: | Line 14: | ||
* [[AJHSME Problems and Solutions]] | * [[AJHSME Problems and Solutions]] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 00:26, 5 July 2013
Problem
The area of the smallest square that will contain a circle of radius 4 is
Solution
Draw a square circumscribed around the circle. (Alternately, the circle is inscribed in the square.) If the circle has radius 
, it has diameter 
. Two of the diameters of the circle will run parallel to the sides of the square. Thus, the smallest square that contains it has side length , and area 
.
See also
| 1997 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
