Difference between revisions of "1997 PMWC Problems/Problem I10"
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| + | == See also == | ||
| + | {{PMWC box|year=1997|num-b=I9|num-a=I11}} | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 13:16, 15 January 2008
Problem
Mary took 24 chickens to the market. In the morning she
sold the chickens at 
7 each and she only sold out less than
half of them. In the afternoon she discounted the price of
each chicken but the price was still an integral number in
dollar. In the afternoon she could sell all the chickens, and
she got totally 132 for the whole day. How many
chickens were sold in the morning?
Solution
Let A be the number of chickens she sold before the discount and B be the number of chickens sold after the discount. Let c be the price of one chicken after the discount.
So c is 5 or less. We make a table of A and c:
c|A
5|6
4|18
So c must equal 5, since when c decreases, A increases.
A=6.
See also
| 1997 PMWC (Problems) | ||
| Preceded by Problem I9 |
Followed by Problem I11 | |
| I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
