Difference between revisions of "1997 PMWC Problems/Problem I11"

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<math>2(w+l)+6w=330</math>
 
<math>2(w+l)+6w=330</math>
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==See also==
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{{PMWC box|year=1997|num-b=I10|num-a=I12}}
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[[Category:Introductory Geometry Problems]]

Revision as of 13:15, 15 January 2008

Problem

A rectangle ABCD is made up of five small congruent rectangles as shown in the given figure. Find the perimeter, in cm, of ABCD if its area is $6750 cm^2$. ABCD.gif

Solution

Let l and w be the length, and width, respectively, of one of the little rectangles.

$3w=2l$

$l=\dfrac{3}{2}w$

$6750=\dfrac{15}{2}w^2$

$w=30$

$l=45$

The perimeter of the big rectangle is

$2(w+l)+6w=330$

See also

1997 PMWC (Problems)
Preceded by
Problem I10
Followed by
Problem I12
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10