Difference between revisions of "1997 PMWC Problems/Problem T5"

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Thus it was either B or C. Since A is telling the truth, C is lying. If D is telling the truth, then B is lying, and E is lying, but that's impossible. Thus D is lying. Then E is telling the truth, and so is B. Thus two people are lying (C and D), and the other three are telling the truth. Since it was one of B or C, and it wasn't B, it must have been C.
 
Thus it was either B or C. Since A is telling the truth, C is lying. If D is telling the truth, then B is lying, and E is lying, but that's impossible. Thus D is lying. Then E is telling the truth, and so is B. Thus two people are lying (C and D), and the other three are telling the truth. Since it was one of B or C, and it wasn't B, it must have been C.
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==See also==
 
==See also==

Revision as of 13:45, 15 May 2012

Problem

During recess, one of five pupils wrote something nasty on the chalkboard. When questioned by the class teacher, the following ensued:

'A': It was 'B' or 'C'

'B': Neither 'E' nor I did it.

'C': You are both lying.

'D': No, either A or B is telling the truth.

'E': No, 'D', that's not true.

The class teacher knows that three of them never lie while the other two cannot be trusted. Who was the culprit?

Solution

Case 1: A is telling the truth

Thus it was either B or C. Since A is telling the truth, C is lying. If D is telling the truth, then B is lying, and E is lying, but that's impossible. Thus D is lying. Then E is telling the truth, and so is B. Thus two people are lying (C and D), and the other three are telling the truth. Since it was one of B or C, and it wasn't B, it must have been C.

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

1997 PMWC (Problems)
Preceded by
Problem T4
Followed by
Problem T6
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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