Difference between revisions of "1999 AHSME Problems/Problem 15"

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==Problem==
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Let <math> x</math> be a real number such that <math> \sec x \minus{} \tan x = 2</math>. Then <math> \sec x \plus{} \tan x =</math>
 
Let <math> x</math> be a real number such that <math> \sec x \minus{} \tan x = 2</math>. Then <math> \sec x \plus{} \tan x =</math>
  
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\textbf{(D)}\ 0.4 \qquad  
 
\textbf{(D)}\ 0.4 \qquad  
 
\textbf{(E)}\ 0.5</math>
 
\textbf{(E)}\ 0.5</math>
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==Solution==
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==See Also==
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{{AHSME box|year=1999|num-b=14|num-a=16}}

Revision as of 20:37, 2 June 2011

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Problem

Let $x$ be a real number such that $\sec x \minus{} \tan x = 2$ (Error compiling LaTeX. Unknown error_msg). Then $\sec x \plus{} \tan x =$ (Error compiling LaTeX. Unknown error_msg)

$\textbf{(A)}\ 0.1 \qquad  \textbf{(B)}\ 0.2 \qquad  \textbf{(C)}\ 0.3 \qquad  \textbf{(D)}\ 0.4 \qquad  \textbf{(E)}\ 0.5$

Solution

See Also

1999 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions