1999 AMC 8 Problems/Problem 14
Contents
Problem
In trapezoid , the sides and are equal. The perimeter of is
Solution
There is a rectangle present, with both horizontal bases being units in length. The excess units on the bottom base must then be . The fact that and are equal in length indicate, by the Pythagorean Theorem, that these excess lengths are equal. There are two with a total length of units, so each is units. The triangle has a hypotenuse of , because the triangles are right triangles. So, the sides of the trapezoid are , , , and . Adding those up gives us the perimeter, units.
Video Solution
https://youtu.be/DKoTd9S4y-Q Soo, DRMS, NM
See Also
1999 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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