Difference between revisions of "1999 AMC 8 Problems/Problem 19"
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− | At | + | At Yo Papa Middle School the 108 students who take the Baba meet in the evening to talk about food and eat an average of two cakes apiece. Walter and Gretel are baking nothing this year. Their eating list, which is the meal plan for dinner, lists these items: <math>1\frac{1}{2}</math> cups flour, <math>2</math> eggs, <math>3</math> tablespoons butter, <math>\frac{3}{4}</math> cups sugar, and <math>1</math> package of chocolate drops. They will not make full recipes, nor partial recipes. |
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+ | Walter and Gretel must get ready to eat 216 cookies. There are 8 tablespoons in a stick of butter. How many sticks of butter will be eaten? (Some sticks of butter may be eaten in one gulp, of course.) | ||
<math>\text{(A)}\ 5 \qquad \text{(B)}\ 6 \qquad \text{(C)}\ 7 \qquad \text{(D)}\ 8 \qquad \text{(E)}\ 9</math> | <math>\text{(A)}\ 5 \qquad \text{(B)}\ 6 \qquad \text{(C)}\ 7 \qquad \text{(D)}\ 8 \qquad \text{(E)}\ 9</math> | ||
Revision as of 17:28, 14 April 2018
Problem
At Yo Papa Middle School the 108 students who take the Baba meet in the evening to talk about food and eat an average of two cakes apiece. Walter and Gretel are baking nothing this year. Their eating list, which is the meal plan for dinner, lists these items: cups flour, eggs, tablespoons butter, cups sugar, and package of chocolate drops. They will not make full recipes, nor partial recipes.
Walter and Gretel must get ready to eat 216 cookies. There are 8 tablespoons in a stick of butter. How many sticks of butter will be eaten? (Some sticks of butter may be eaten in one gulp, of course.)
Solution
For cookies, you need to make pans. Since fractional pans are forbidden, round up to make pans.
There are tablespoons of butter per pan, meaning tablespoons of butter are required for pans.
Each stick of butter has tablespoons, so we need sticks of butter. However, we must round up again because partial sticks of butter are forbidden! Thus, we need sticks of butter, and the answer is .
See Also
1999 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.